In equilbrium,
net force = 0
Let T be the tension of the string,
In y-direction,
..................................(1)
In x-direction,
....................................(2)
By solving (1) and (2), we can get F = 8.5 (corr to 1 d.p.)
In equilbrium,
net force = 0
Let T be the tension of the string,
In y-direction,
..................................(1)
In x-direction,
....................................(2)
By solving (1) and (2), we can get F = 8.5 (corr to 1 d.p.)